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Work, Energy and Power: Definitions, Formulas, Types of Energy, Law of Conservation of Energy, Work-Energy Theorem, and Complete CBSE Guide

A comprehensive guide to work, energy and power for CBSE Class 9 and Class 11 Physics — definitions, formulas, kinetic and potential energy, mechanical energy, work-energy theorem, conservation of energy, power and efficiency, real-world examples, and solved numerical problems.
28 July 2026 by
Work, Energy and Power: Definitions, Formulas, Types of Energy, Law of Conservation of Energy, Work-Energy Theorem, and Complete CBSE Guide
AJKANT OVERSEAS, Krishan Kant
● CBSE Class 9 & Class 11 Physics — Work, Energy and Power

Every time you climb a staircase, kick a football, or turn on a light switch, you are using energy to do work or convert it from one form to another. The concepts of work, energy, and power are not merely physics definitions — they are the language in which the universe describes every physical process, from the falling of an apple to the nuclear fusion burning inside the Sun.

In physics, work is done only when a force causes displacement in its own direction. Energy is the capacity to do work — it can take many forms (kinetic, potential, thermal, electrical, chemical, nuclear) but can never be created or destroyed, only converted. Power is the rate at which work is done or energy is transferred. Together, these three concepts form the foundation of mechanics and thermodynamics.

For CBSE Class 9 Physics Chapter 11 (Work and Energy) and CBSE Class 11 Physics Chapter 6 (Work, Energy and Power), these topics appear in every board examination and are prerequisites for understanding thermodynamics, electricity, and modern physics. This guide covers all subtopics: work done formula and conditions, kinetic energy, potential energy, mechanical energy, the work-energy theorem, the law of conservation of energy, power, efficiency, and five CBSE exam-ready solved problems.

Work
Work Done by Force
W = F · s · cosθ
Unit: Joule (J) = N·m | Scalar quantity
Energy
Kinetic + Potential
KE = ½mv² | PE = mgh
Unit: Joule (J) | Scalar quantity
Power
Rate of Doing Work
P = W/t = Fv
Unit: Watt (W) = J/s | Scalar quantity

1. Work — Definition, Formula, Conditions

⚠ Definition of Work in Physics
W = F s cosθ
Work is said to be done when a force acting on a body causes a displacement of the body in the direction of the force (or has a component in the direction of displacement).

Variables: W = work done (Joules)  |  F = force applied (Newtons)  |  s = displacement (metres)  |  θ = angle between force and displacement

Unit: 1 Joule (J) = 1 Newton × 1 metre = 1 N·m
Definition of 1 Joule: One joule of work is done when a force of 1 N causes a displacement of 1 m in the direction of the force.

Three conditions for work to be done:
(1) A force must be applied to the body.
(2) The body must be displaced (move).
(3) The force must have a component in the direction of displacement (θ must not be 90°).

Special cases of angle θ:
• θ = 0° (force parallel to displacement): W = Fs — maximum positive work (e.g., pushing a box in the direction of motion)
• θ = 90° (force perpendicular to displacement): W = 0 — no work done (e.g., carrying a bag horizontally, gravity on circular orbit)
• θ = 180° (force opposite to displacement): W = −Fs — negative work done (e.g., friction opposes motion, braking force)

When Is Work NOT Done?

👩‍🏫
Carrying a bag horizontally
You hold a bag (upward force) and walk horizontally (displacement). θ = 90° between force and displacement, so W = Fs cos90° = 0. No work done by the holding force (though you feel tired due to muscular work).
🌏
Satellite in circular orbit
Gravity acts toward Earth’s centre; satellite moves tangentially (perpendicular to gravity). θ = 90°, so gravity does no work on the satellite — its speed remains constant.
🏗
Pushing a wall that doesn’t move
A large force is applied but displacement = 0. W = F × 0 = 0. No displacement = no work. Your muscles are doing internal biological work, but no mechanical work is done on the wall.
📷
Normal force on a moving body
The normal force from the ground acts vertically upward on a body moving horizontally. Since force is perpendicular to displacement, W = 0. Normal force does no work on a body moving on a flat surface.

2. Energy — Definition and Types

Energy is defined as the capacity or ability to do work. An object that has energy can exert a force on another object and do work on it. Energy is a scalar quantity measured in Joules (J). Like work, it cannot be seen directly but its effects are observable.

Kinetic Energy
Energy possessed by a body due to its motion. KE = ½mv². Examples: moving car, flowing water, flying bird.
🏠
Gravitational Potential Energy
Energy stored due to position above a reference level. PE = mgh. Examples: water in a dam, raised hammer, stretched spring.
🔥
Thermal (Heat) Energy
Energy associated with temperature — the kinetic energy of molecules. Examples: hot water, steam engine, body heat.
🔌
Electrical Energy
Energy carried by moving electric charges. Examples: electricity in wires, lightning, batteries. W = VIt = Pt.
Chemical Energy
Energy stored in chemical bonds. Released in combustion, metabolism, batteries. Examples: petrol, food, explosives.
Nuclear Energy
Energy stored in atomic nuclei. Released in fission (nuclear reactor) or fusion (Sun). E = mc² (Einstein’s mass-energy relation).

3. Kinetic Energy — Formula and Derivation

▶ Kinetic Energy (KE)
KE = ½ m v²
Definition: The kinetic energy of a body is the energy it possesses by virtue of its motion.

Derivation using work-energy theorem:
Consider a body of mass m starting from rest (u = 0) and accelerated by a constant force F through a displacement s.
• By Newton’s second law: F = ma
• Work done: W = F × s = mas
• By kinematics: v² = u² + 2as ⇒ v² = 2as (since u = 0) ⇒ as = v²/2
• Substituting: W = m × (v²/2) = ½mv²
This work done = kinetic energy gained: KE = ½mv²

Key properties of KE:
• KE is always positive (or zero). It cannot be negative.
• KE depends on the square of velocity: doubling speed quadruples KE.
• KE is a scalar quantity (no direction).
• A body at rest has KE = 0.
• Relation with momentum p: KE = p²/2m (since p = mv, KE = ½mv² = m²v²/2m = p²/2m)

4. Potential Energy — Gravitational and Elastic

⇧ Gravitational Potential Energy (GPE)
PE = mgh
Definition: The potential energy possessed by a body due to its position above a reference level (usually the ground).

Derivation:
To lift a body of mass m to a height h, we must apply an upward force equal to its weight (F = mg) through a displacement h.
Work done against gravity: W = F × h = mg × h = mgh
This work done is stored as gravitational potential energy: PE = mgh

Variables: m = mass (kg)  |  g = acceleration due to gravity (9.8 m/s² ≈ 10 m/s²)  |  h = height above reference level (m)

Note: PE depends on the chosen reference level. It is the change in PE (ΔPE = mgΔh) that matters physically, not the absolute value.
Elastic Potential Energy (Spring)
PEᵉ = ½ k x²
k = spring constant (N/m)  |  x = extension or compression of spring (m)
When a spring is stretched or compressed by x from its natural length, it stores elastic PE = ½kx².
Examples: compressed spring, stretched rubber band, bow drawn before shooting arrow, car suspension spring.

5. Work-Energy Theorem

▶ Work-Energy Theorem
Wᵗᵃᵗ = ΔKE = ½mv² − ½mu²
Statement: The net work done on a body equals the change in its kinetic energy.

Derivation:
For a body of mass m with initial velocity u and final velocity v under constant net force F through displacement s:
• By kinematics: v² = u² + 2as ⇒ as = (v² − u²)/2
• Net work: W = Fs = mas = m(v² − u²)/2 = ½mv² − ½mu²
• W = KEᵓ − KEᵢ = ΔKE

Applications:
• If net work is positive (W > 0), KE increases (object speeds up).
• If net work is negative (W < 0), KE decreases (object slows down).
• If W = 0, KE is unchanged (constant speed, e.g., uniform circular motion).
• Used to find velocity after a known work is done: v = √(u² + 2W/m)

6. Law of Conservation of Energy

Law of Conservation of Energy: Energy can neither be created nor destroyed; it can only be converted from one form to another. The total energy of an isolated system remains constant.

For mechanical energy: Total Mechanical Energy = KE + PE = constant (in absence of friction/non-conservative forces)
At any point: ½mv² + mgh = constant = Total Mechanical Energy (E)

📈 Free-Falling Ball — Energy Conservation at Every Point

Height h Ball at rest PE = mgh KE = 0 Total E = mgh (Top) v = 0 m/s PE is maximum KE is minimum E = mgh Height h/2 Ball moving PE = mg(h/2) KE = mg(h/2) Total E = mgh (Middle) v = sqrt(gh) PE = KE KE = PE E = mgh Height 0 Ball at max speed PE = 0 KE = mgh Total E = mgh (Bottom) v = sqrt(2gh) PE is minimum KE is maximum E = mgh At every point: KE + PE = mgh = constant (Total Mechanical Energy conserved)

This is why a pendulum bob swings back and forth indefinitely in the absence of air resistance — mechanical energy is continuously converted between kinetic (at lowest point) and potential (at highest point) while the total remains constant.

7. Power and Efficiency

⚡ Power — Rate of Doing Work
P = W/t = F v
Definition: Power is the rate at which work is done or energy is transferred. It tells us how quickly work is done, not how much work is done.

Unit: 1 Watt (W) = 1 Joule per second (J/s) = 1 N·m/s
Commercial unit: 1 kilowatt-hour (kWh) = 1000 W × 3600 s = 3.6 × 10&sup6; J = 3.6 MJ (the unit of electrical energy in electricity bills).
Older unit: 1 horsepower (hp) = 746 W ≈ 0.746 kW

Power in terms of velocity: P = W/t = (F·s)/t = F·(s/t) = F·v (where v = s/t = average velocity)

Average power: Pᵃᵛᵉ = Total work done / Total time = Wᵗᵃᵗᵃᵈ / t
Instantaneous power: Pᵢᵗᴸᵗ = dW/dt = F·v (at that instant)
Efficiency of a Machine
η = (Useful Output Energy / Total Input Energy) × 100%
η = efficiency (dimensionless, expressed as %)  |  Always η ≤ 100% (due to energy losses as heat, sound, etc.)
Also: η = (Useful Output Power / Total Input Power) × 100%
Example: A motor consumes 1000 W of electrical power and delivers 750 W of mechanical power. Efficiency = (750/1000) × 100 = 75%.
The remaining 25% (250 W) is lost as heat in the motor windings and friction in bearings.

8. Work, Energy and Power — Comparison Table

PropertyWork (W)Energy (E)Power (P)
DefinitionForce × displacement (in direction of force)Capacity to do workRate of doing work
FormulaW = Fs cosθKE = ½mv²; PE = mghP = W/t = Fv
SI UnitJoule (J)Joule (J)Watt (W = J/s)
Type of quantityScalarScalarScalar
Can be negative?Yes (opposing force)KE: No. PE: Depends on referenceNo (rate is positive)
Dimensional formula[ML²T²][ML²T²][ML²T³]
RelationW = P × tE = W (work done = energy transferred)P = E/t = W/t
Commercial unitkilowatt-hour (kWh)kilowatt-hour (kWh)kilowatt (kW), horsepower (hp)

9. Solved Numerical Problems

Q1. A force of 50 N acts on a body at an angle of 60° to the displacement of 10 m. Calculate the work done.
Given: F = 50 N  |  s = 10 m  |  θ = 60°
W = F s cosθ = 50 × 10 × cos 60° = 50 × 10 × 0.5 = 250 J
W = 250 J
Q2. A car of mass 1000 kg is moving at 20 m/s. Calculate its kinetic energy. Also find its kinetic energy if its speed doubles to 40 m/s.
Given: m = 1000 kg  |  v₁ = 20 m/s  |  v₂ = 40 m/s
KE₁ = ½mv² = ½ × 1000 × 20² = 500 × 400 = 200,000 J = 200 kJ
KE₂ = ½mv² = ½ × 1000 × 40² = 500 × 1600 = 800,000 J = 800 kJ
Note: Doubling the speed quadruples the KE (KE ∝ v²): 800 kJ = 4 × 200 kJ ✓
KE at 20 m/s = 200 kJ  |  KE at 40 m/s = 800 kJ (4 times larger)
Q3. A ball of mass 0.5 kg is thrown upward with a velocity of 10 m/s. Using conservation of energy, find the maximum height reached. (g = 10 m/s²)
Given: m = 0.5 kg  |  u = 10 m/s  |  g = 10 m/s²  |  v = 0 (at maximum height)
At the bottom: KE = ½mu² = ½ × 0.5 × 10² = 25 J, PE = 0
At the top: KE = 0 (momentarily at rest), PE = mgh
By conservation of energy: KEᵉᵓᵗᵗᵓᵖ = PEᵗᵓₚ
25 = mgh = 0.5 × 10 × h
h = 25/5
Maximum height h = 5 m
Q4. A machine lifts a load of 200 kg to a height of 5 m in 10 seconds. Calculate the power developed by the machine. (g = 10 m/s²)
Given: m = 200 kg  |  h = 5 m  |  t = 10 s  |  g = 10 m/s²
Work done against gravity: W = mgh = 200 × 10 × 5 = 10,000 J
Power: P = W/t = 10,000/10 = 1,000 W = 1 kW
P = 1000 W = 1 kW
Q5. Using the work-energy theorem, find the velocity of a body of mass 2 kg after a net force of 10 N acts on it through a distance of 5 m, starting from rest.
Given: m = 2 kg  |  F = 10 N  |  s = 5 m  |  u = 0 m/s
Net work done: W = F × s = 10 × 5 = 50 J
By Work-Energy Theorem: W = ΔKE = ½mv² − ½mu²
50 = ½ × 2 × v² − 0
50 = v²
v = √50 = 5√2
v = 5√2 ≈ 7.07 m/s

10. Real-World Applications

🇮🇳
Hydroelectric Power Plants
Water stored at height h has gravitational PE = mgh. Falling water converts PE to KE, which spins turbines (KE to mechanical energy), which drive generators (mechanical to electrical energy). Conservation of energy at every stage.
🚗
Car Braking (KE to Thermal)
When brakes are applied, friction does negative work on the car, reducing KE. The KE is converted to heat energy in the brake pads. Regenerative braking in electric vehicles converts KE back to electrical energy stored in the battery.
🏝
Roller Coasters
A roller coaster at the top of the first hill has maximum PE and minimum KE. As it descends, PE converts to KE (it speeds up). At the bottom, KE is maximum. Energy continuously converts between PE and KE throughout the ride, with some lost to friction and air resistance.
Railway Locomotive Power Rating
A locomotive rated at 2000 kW means it can deliver 2000 kJ of work per second. This power rating determines how fast it can pull a given load on a slope: P = Fv, so at a given speed, the maximum towing force is F = P/v.
🌞
Solar Energy Conversion
Solar panels convert light (electromagnetic energy) to electrical energy (photovoltaic effect). Each photon has energy E = hf (Planck’s law). Panel efficiency (η) tells what fraction of incident solar energy is converted to electricity, typically 15–22% for commercial panels.
🏃
Human Body (Food to Mechanical Energy)
Calories in food are chemical energy. The body converts chemical energy to thermal energy (body heat) and mechanical energy (muscles doing work). A 70 kg person climbing 100 stairs (each 20 cm high) does W = mgh = 70×10×20 = 14,000 J ≈ 3.3 Calories of mechanical work.

11. Frequently Asked Questions (FAQ)

Q1. What is the SI unit of work and energy? Define 1 Joule.

The SI unit of both work and energy is the Joule (J), named after James Prescott Joule.

1 Joule is defined as: The amount of work done when a force of 1 Newton causes a displacement of 1 metre in the direction of the force.
1 J = 1 N·m = 1 kg·m²/s²

Other units of energy:
• 1 kilowatt-hour (kWh) = 3.6 × 10&sup6; J = 3.6 MJ (unit of electrical energy in bills)
• 1 calorie (cal) = 4.18 J (used in nutrition)
• 1 electron-volt (eV) = 1.6 × 10²³ J (used in atomic physics)

Q2. When is work said to be negative? Give two examples.

Work done by a force is negative when the force acts opposite to the direction of displacement (θ = 180°, cos 180° = −1), giving W = −Fs.

Examples of negative work:
(1) Friction on a moving body: A book slides across a table. Friction acts backward (opposite to motion), doing negative work: W = −f·s. This negative work reduces the book’s kinetic energy until it stops.
(2) Braking force on a car: Brakes apply a backward force on a forward-moving car. The braking force does negative work (W = −Fs), reducing the car’s KE from ½mv² to zero.
(3) Gravity on a rising ball: A ball thrown upward: gravity acts downward while displacement is upward. Wᵭᵅᵃᵗᵀ = −mgh (negative), which reduces the ball’s KE as it rises.

Q3. State and explain the law of conservation of energy with an example.

Law of Conservation of Energy: Energy can neither be created nor destroyed. It can only be converted from one form to another. The total energy of an isolated system remains constant.

Example — Free-falling ball: A ball of mass m held at height h has PE = mgh, KE = 0. Total mechanical energy = mgh.
As it falls, PE decreases and KE increases. At height h/2: PE = mgh/2, KE = mgh/2. Total = mgh ✓
Just before hitting the ground (height = 0): PE = 0, KE = mgh = ½mv² ⇒ v = √(2gh). Total = mgh ✓
At every point, KE + PE = mgh = constant. After hitting the ground, KE converts to heat and sound — energy is still conserved, just in different forms.

Practical consequence: No machine can ever deliver more energy than it receives (efficiency ≤ 100%). If a machine claims to produce more energy than it consumes, it violates conservation of energy and must be fraudulent.

Q4. What is the work-energy theorem? How is it useful?

Work-Energy Theorem: The net work done on a body equals the change in its kinetic energy.
Wᵗᵃᵗ = KEᵓᵢᵗᵃᵈ − KEᵢᵗᵢᵗᵢᵃᵈ = ½mv² − ½mu²

Derivation (brief): From Newton’s second law and kinematics: F = ma and v² = u² + 2as ⇒ W = Fs = mas = m(v² − u²)/2 = ΔKE.

Usefulness:
(1) Calculates final speed after a given work input without knowing acceleration: v = √(u² + 2W/m).
(2) Finds work done by individual forces (e.g., friction) by comparing energy changes.
(3) Explains stopping distance of vehicles: W = −fs (friction does negative work), ½mv² = fs ⇒ s = mv²/(2f). Doubling speed requires 4 times longer stopping distance — a critical road safety insight.

Q5. What is the difference between work and power?

Work (W): Work is the product of force and displacement in the direction of force (W = Fs cosθ). It measures the total amount of energy transferred. Doing more work means more energy was used, but it says nothing about how quickly it was done. Unit: Joule (J).

Power (P): Power is the rate at which work is done (P = W/t). It measures how quickly work is done or energy is transferred. Two machines doing the same amount of work can have different powers if they take different times. Unit: Watt (W = J/s).

Example: A person carries a 50 kg box up a 10 m staircase in 20 seconds; a crane does the same in 5 seconds. Both do W = mgh = 50×10×10 = 5000 J of work. But the crane’s power P = 5000/5 = 1000 W = 1 kW; the person’s power P = 5000/20 = 250 W. Same work, four times more power for the crane (faster rate).

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